just as A do, so do B
be known as +n.
be known to do sth. 对 be known for doing sth,错
我觉得B选项的错误在于ultimate这个词是形容goal,而不是改成ultimately修饰reduce。
看到解释后真的脑袋一阵嗡
what happened in 1999?
the passage of the law happened in 1999.
therefore, "in 1999" should be placed as close as possible to "the passage". the placement in this choice is ideal.
韦恩图
E 最后的that从句不缺成分,一定不是定语从句,由于后面的话,和degree不是等同的关系,也不是同位语从句。
D 为什么要用to which呢。。
high wheels和floors平行
mice是复数
根据题设可知一共有五种情况(4颗糖豆不是红就是黑):0Black(B) 4Red(R),1B 3R, 2B 2R, 3B 1R, 4B 0R.
题设中的两个条件:A在交换前, X碗中有两个黑色
B 在交换后,Y碗中各有一种颜色。
不论是一起成立还是单一成立,都无法满足所有五种条件,因此选E
that 指代 animals, plural --> exhibit (a)(b) eliminated
(e) expand & include 是因果關係,不是並列關係。(e) eliminated
either...or 位置 (c) eliminated
即问:削弱新车增加——氮排放减少。
Unlike 的比較對象,不會是 workers, company, (a)(b)(c) eliminated
(e) the last day that they are scheduled to collect,collect days is illogical
这题太绕了。。。。
(a)(b) meaning 有問題
a. Suppliers are growing fish twice as fast as suppliers are growing their natural growth rate. (受詞代替fish)
b. Suppliers are growing fish twice as fast as their natural growth rate is growing fish. (主詞代替suppliers)
(c)
兩倍速成長-->人為的,自然成長-->非人為的,所以不會growing them
(e)
平行(growing, cutting, raising)
it 指代模糊,(a)(b) eliminated
both increase.... and compete... 且 than ____ did in the past,底線處代指的是 "the airline" 為單數,(c)(e) eliminated
(1) the greatest common factor of m and p is 2 --> both p and m are even (as both have 2 as a factor) --> even divided by even can give only even remainder (0, 2, 4, ...), since remainder is not zero (as pm≠integer), then remainder must be more than 1: 2, 4, ... Sufficient.
(1) 16 students at the school study both French and Japanese.
(2) 10 percent of the students at the school who study Japanese also study French.
「比大小的題目,要注意 知道 『絕對數量』 或是 『相對比例』都能破解」!
The operation @ represents either addition, subtraction, or multiplication of integers. What is the value of 1 @ 0 ?
(1) 0@2 =2, @ = + --> sufficient
(2) 2@0 =2, @ = + or -, HOWEVER, 1+0 or 1-0 都等於 1, --> sufficient
If n and p are integers, is p > 0?
(1) n + 1 > 0
(2) np > 0
(1) n+1>0 且 n 是整數,則 n = 0,1,2,3,4,......... ->not sufficient
(2) np>0, n&p>0 or n&p not sufficient
(1)(2) n&p>0 -> sufficient
any positive integer root from a number more than 1 will be more than 1