The cardinality of a finite set is the number of elements in the set. What is the cardinality of setA?
(1)2 is the cardinality of exactly 6 subsets of set A.
(2)Set A has a total of 16 subsets,including the empty set and set A itself.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
题目:一个有限集的cardinality 就是这个集合元素的个数,问集合A的元素个数。
(1)集合A中恰好有6个子集的元素个数为2
(2)集合A共有16个子集,包括空集和它本身
知识点:
一个有限集合有2^n个子集,其中n为该有限集合中的元素个数,非空子集有2^n - 1 个
(1)集合A中元素取2个有6中不同的取法,Cn2 = 6, n = 4, 即集合A有4个元素
(2)2^n = 16, n = 4, 即集合A有4个元素
牛!!!
妙啊妙啊(诸葛音)
好厉害!一直不懂这种题
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