If x+y+z>0, is z>1?
(1)z>x+y+1
(2)x+y+1<0
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
【引用】-考察不等式的运用算
不等式的运算及推理:
(1)z>x+y+1&x+y+z>0得出x+y+x+y>-1, x+y>-1/2. 【由题目条件可得:由z>x+y+1可知,z要大于1则必须x+y>0,】无法满足。
(2)x+y+10得出一个小于-1的数+z>0,则z必须大于1.
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