What is the ratio of the average (arithmetic mean) height of students in class X to the average height of students in class Y?
(1) The average height of the students in class X is 120 centimeters.
(2) The average height of the students in class X and class Y combined is 126 centimeters.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
注意 combined 的含义 不是(x平均+y平均)除以2之后是126 而是(x总height+y总height)除以(x+y)是126 所以选E不满足
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设平均数为x,y,人数为a,b。求x/y
(1)x=120
(2) (ax+by)/(a+b)=126-->120a+by=126a+126b,三元一次方程除非接触x等于y的倍数,不带尾数,才能得出x/y,四元一次方程更难。
(1)(2)联立,得出y=6(a/b)+126,不知道a/b,无法求出x/y的值。
两组不一定人数相同,相同成立
X班: 平均身高 a 设有M个人 Y班 : 平均升高 设为 b cm 设有N 个人 问题是求120:b
条件1. a=120 ---> OUT
条件2. 总共平均身高126---> out
1和2 一起 126*(m+n)= 120*m+b*n----> 由总人数相等列出等式 目的是求这个b 化简之后 b=6m/n+126 由此可见必须要得到M/N的比值才可以。