If he is to ride 3 times and since he can choose any of the 3 cars each time, total number of ways is
= 3 * 3 * 3
= 27

Now the number of ways if he is to choose a different car each time is
= 3 * 2 * 1
= 6

So the probability is
= 6/27
= 2/9

第一次选择为1/3，第二次选择为2/3，第三次选择为1，所以 1/3*2/3*1= 2/9

题目看错，what is the probability that the passenger will ride in eachof the 3 cars? 乘客三次分别乘坐这三辆不同车的概率

what is the probability that the passenger will ride in eachof the 3 cars?题目没有读懂做错-题目的意思应该是passenger每一个car都做过的概率因为是 “ride in each(每一个)”，所以就是：1/3*2/3*1=2/9

如果是抛硬币等互不干扰事件，3次的概率=每次的概率的立方
过山车的车厢是被拴着的，知道第一次坐的是哪节车厢、第二次坐的是哪节，所以第二次乘坐时可以把第一次乘坐的车厢排除掉，不属于互不干扰事件。

A(3_3)=6 , there are 6 ways to choose the bike in total.
the probability of each bike be chosen is 1/3

1/3*1/3*1/3*6=2/9

this formula means: there are 6 ways that each bike will be chosen.(ABC ACB BAC BCA CAB CBA), and each time the probability of the group is 1/3*1/3*1/3.
so, the totally probablity is 6 times 1/27, which is 2/9

哭了 3*3*3我为什么会算成9....

3*2*1/3*3*3

独立事件——一共有27种可能。每一个过山车都坐过：3*2*1=6种

If he is to ride 3 times and since he can choose any of the 3 cars each time, total number of ways is
= 3 * 3 * 3
= 27

Now the number of ways if he is to choose a different car each time is
= 3 * 2 * 1
= 6

So the probability is
= 6/27
= 2/9

1/3*2/3*1=2/9

这是排列组合里的排列，看顺序的。

P(3,3)*1/3^3

1/3*1/3*1/3*A(3,3)

If he is to ride 3 times and since he can choose any of the 3 cars each time, total number of ways is
= 3 * 3 * 3
= 27

Now the number of ways if he is to choose a different car each time is
= 3 * 2 * 1
= 6

So the probability is
= 6/27
= 2/9