Acertain roller coaster has 3 cars, and a passenger is equally likely to ride inany 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the rollercoaster 3 times, what is the probability that the passenger will ride in eachof the 3 cars?
0
~$\frac{1}{9}$~
~$\frac{2}{9}$~
~$\frac{1}{3}$~
1
A(3_3)=6 , there are 6 ways to choose the bike in total.
the probability of each bike be chosen is 1/3
1/3*1/3*1/3*6=2/9
this formula means: there are 6 ways that each bike will be chosen.(ABC ACB BAC BCA CAB CBA), and each time the probability of the group is 1/3*1/3*1/3.
so, the totally probablity is 6 times 1/27, which is 2/9
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