Acertain roller coaster has 3 cars, and a passenger is equally likely to ride inany 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the rollercoaster 3 times, what is the probability that the passenger will ride in eachof the 3 cars?
0
~$\frac{1}{9}$~
~$\frac{2}{9}$~
~$\frac{1}{3}$~
1
If he is to ride 3 times and since he can choose any of the 3 cars each time, total number of ways is
= 3 * 3 * 3
= 27
Now the number of ways if he is to choose a different car each time is
= 3 * 2 * 1
= 6
So the probability is
= 6/27
= 2/9
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