The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
16
18
19
20
22
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Picking the answer choices start form C upwards (K+M+R+S+T)/5=16 K+M+R+S+T=80 K+M+R+S+40=80 1+2+18+19+40=80
注意是正整数
k < m < r < s < t，不能有相等的数！
k < m < r < s < t
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Picking the answer choices
start form C upwards
(K+M+R+S+T)/5=16
K+M+R+S+T=80
K+M+R+S+40=80
1+2+18+19+40=80
注意是正整数
k < m < r < s < t，不能有相等的数！
k < m < r < s < t