On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
~$33\frac{1}{3}$~%
40%
50%
60%
~$66\frac{2}{3}$~%
If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, so 40 percent took
0.2x=0.4y y/x=0.5
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