In the figure, each side of square ABCD has length 1, the length of line segment CE is 1, and the length of line segment BE is equal to the length of line segment DE. What is the area of the triangular region BCE?
~$\frac{1}{3}$~
~$\frac{\sqrt{2}}{4}$~
~$\frac{1}{2}$~
~$\frac{\sqrt{2}}{2}$~
~$\frac{3}{4}$~
这居然是个平面几何。。。这也太坑了。。。
“连接正方形对角线,交点为o。BCE的面积=BOE的面积-BOC的面积”
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