In the figure, each side of square ABCD has length 1, the length of line segment CE is 1, and the length of line segment BE is equal to the length of line segment DE. What is the area of the triangular region BCE?
~$\frac{1}{3}$~
~$\frac{\sqrt{2}}{4}$~
~$\frac{1}{2}$~
~$\frac{\sqrt{2}}{2}$~
~$\frac{3}{4}$~
用时太长了!考试估计要直接跳过了。图太有误导性。利用了等腰三角形底边高与底边中分线是同一条线的性质,所以AC和CE在一条线上。BD垂直AC,所以直接底乘高除2 可得
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