There are 8 magazines lying on a table; 4 are fashion magazines and the other 4 are sports magazines. If 3 magazines are to be selected at random from the 8 magazines, what is the probability that at least one of the fashion magazines will be selected?
~$\frac{1}{2}$~
~$\frac{2}{3}$~
~$\frac{32}{35}$~
~$\frac{11}{12}$~
~$\frac{13}{14}$~
{at least one}={total}-{none}
total: 8*7*6 / 3! =56
none: 4*4*2 / 3! = 4
at least one = 56-4 = 52
probability = 52/56 = 13/14
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