If 2 different representatives are to be selected at random from a group of 10 employees and if p is the probability that both representatives selected will be women, is p > ~$\frac{1}{2}$~ ?
(1) More than ~$\frac{1}{2}$~ of the 10 employees are women.
(2) The probability that both representatives selected will be men is less than ~$\frac{1}{10}$~
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
题目分析:
(1) 10人中超过~$\frac{1}{2}$~的为女性,不知道女性员工的具体数目,也就无法计算每次挑选员工为女性概率的值。
(2) 挑选的2名员工全为男性的概率小于~$\frac{1}{10}$~,也无法计算男性员工或女性员工的具体数目,也无法计算挑选到女性员工的概率。
因此,本题答案为(E),两个条件结合起来也不能解题,必须提供新数据。
可以计算范围,但是得到了范围依旧存在大于1/2和小于1/2的情况
不可以用概率运算吗
C5.2/C10.2.
stmt1: More than 1/2 of 10 employees are women.
case 1: 6 women , 4 men
probability of selecting 2 women is (6/10)*(5/9) = 1/3
条件一推出x>5
条件2推出x>6