If 1050 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
424
433
440
449
467
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9*48+2+6.。。。。。。不是9*47,最好用举例法验证一下
粗心把sum算成了48*9+26,扶额
48*9+2+6=440
找规律 10^3 = 1000 - 74 = 926 10^4 = 10000-74 = 9926 10^5 = 100000 - 74 = 99926 规律:50-2=48个9和26 所以: 48*9+2+6 = 432 + 2 + 6 = 440
一共48个9,不是47个
If 1050 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?如何求解,同学们?
9*48+2+6.。。。。。。不是9*47,最好用举例法验证一下
粗心把sum算成了48*9+26,扶额
48*9+2+6=440
找规律
10^3 = 1000 - 74 = 926
10^4 = 10000-74 = 9926
10^5 = 100000 - 74 = 99926
规律:50-2=48个9和26
所以:
48*9+2+6
= 432 + 2 + 6
= 440
一共48个9,不是47个
If 1050 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?如何求解,同学们?