Adult female rats who have never before encountered rat pups will start to show maternal behaviors after being confined with a pup for about seven days. This period can be considerably shortened by disabling the female's sense of smell or by removing the scent-producing glands of the pup.
Which of the following hypotheses best explains the contrast described above?
The sense of smell in adult female rats is more acute than that in rat pups.
The amount of scent produced by rat pups increases when they are in the presence of a female rat that did not bear them.
Female rats that have given birth are more affected by olfactory cues than are female rats that have never given birth.
A female rat that has given birth shows maternal behavior toward rat pups that she did not bear more quickly than does a female rat that has never given birth.
The development of a female rat's maternal interest in a rat pup that she did not bear is inhibited by the odor of the pup.
这道题的文段,有2个推理:
推理1:没有怀孕的母老鼠 + 刚出生的小老鼠——> 有母性行为出现
推理2:出现母性行为的没有怀孕的母老鼠+去掉这些母老鼠的嗅觉+去掉小老鼠的腺体——>母性行为的时间缩短
问题问的是,推理1和推理2之间的gap在哪里?(为什么推理1和推理2两件事情都会发生)
所以当然是E啦:因为让母老鼠产生母性行为的核心原因是小老鼠的味道Odor,所以当科学家将母老鼠的嗅觉除掉,以及把小老鼠排汗的腺体去掉,母老鼠就闻不到小老鼠的味道,因此就会缩短shortern 母性泛滥的时间了
登录 或 注册 后可以参加讨论