Is the product of a certain pair of integers even?
(1) The sum of the integers is odd.
(2) One of the integers is even and the other is odd.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
奇数+偶数=奇数
奇数*偶数=偶数
(1)中有可能其中一个是0,另一个是奇数不是不能确定吗?
1. 0 is an integer.
2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.
3. 0 is neither positive nor negative integer (the only one of this kind).
4. 0 is divisible by EVERY integer except 0 itself.
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看到奇偶的题目要十万分注意!!
加减法运算中:只有 奇数+偶数=奇数
乘除法运算中:只有 奇数*奇数=奇数
pair看清题目
a certain pair of
注意pair, 一对,以及the ohter。 这些代表了一共就两个数字
a certain pair of integers两个数!!!!!!已经知道有多少数字了!!!!!
a pair of integers 只有两个数...在脑补啥呢
那奇数乘奇数是奇数,偶数乘偶数是偶数啊,第一个怎么确定?
"The sum of the integers is odd.",只有一个奇数+一个偶数才可能等于奇数。所以必是一奇一偶
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odd+even=odd
odd+odd=even
even+even=even
pair of 一对