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题库 / Prep2007E1-DS-112
Each person attending a fund-raising party for a certain club was charged the same admission fee. How many people attended the party?
(1) If the admission fee had been $0.75 less and 100 more people had attended, the club would have received the same amount in admission fees.
(2) If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
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归因：本质是计算的问题。无法确认两个等式是否为同一个等式
- -没看懂题目
原来不是用xy去替换，是直接展开两个方程连立求解，好阴险。。。G里面好多这样的题目要你把方程化到最简。。。注意力。。。
(1) xy=(x-0.75)*(y+100)
100x-0.75y=75
(2) xy=(x+1.5)*(y-100)
100x-1.5y=150
(x-0.75)*(y+100)=(x+1.5)*(y-100)
xy+100x-0.75y-75=xy-100x+1.5y-150
200x-2.25y+75=0
请问这个式子怎么求解。。。
there are 2 items need to be calculate, we think it's impossible to do, but the equation can.
直接忽略xy好尴尬 分别求不等式
等式联立后还是二元一次的方程，（x-0.75)*(y+100)=(x+1.5)*(y-100)，还是求不出来，我是不是miss了什么信息？
超尴尬，都看不懂题。
1)假设票价x,参加的人是y，xy=(x-0.75)*(y+100),有两个未知数不能求出y
2)xy=(x+1.5)*(y-100），同上不能求出y
1)+2)两式联立能分别求出x,y
哈哈 同尴尬
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