If the terms of a sequence are t1, t2, t3, . . . , tn, what is the value of n ?
(1) The sum of the n terms is 3,124.
(2) The average (arithmetic mean) of the n terms is 4.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
然后就是简单的 平均数*个数=总和
因为题干说了是连续sequence登录 或 注册 后可以参加讨论
【引用】
1)t1+t2+t3+...+tn=3124,t1,t2,t3的特点未知,不能求出n
2)只知道平均数,不知道总数也不能求出n
1)+2) 4n=3124 n=781
所以无论tn的表达式怎么变化,n可以求出来
consecutive integers: (递增的)连续整数
基础知识、解题思路都有,真正导致结果不理想的因素有:对题意理解的速度慢、细节不注意、计算推导不够快、时间紧迫感导致的慌乱、以及慌乱后导致的不check,选项混淆
2)只知道平均数,不知道总数也不能求出n
1)+2) 4n=3124
n=781
犯了同样的错误登录 或 注册 后可以参加讨论
n=781
解题思路:average = sum / number of data points
average = sum / number of data points
or
(average)(number of data points) = sum