If 0 < x < 1, what is the median of the values ~$x, x^{-1}, x^{2}, \sqrt{x}, $~ and ~$x^{3}$~?
~$x$~
~$x^{-1}$~
~$x^{2}$~
~$\sqrt{x}$~
~$x^{3}$~
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x = 1/4 x^-1 = 4 x^2 = 1/16 x^(1/2) = 1/2 x^3 = 1/8. From this, rearrange the number and the median is 1/4, which is x. Answer A
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x = 1/4
x^-1 = 4
x^2 = 1/16
x^(1/2) = 1/2
x^3 = 1/8.
From this, rearrange the number and the median is 1/4, which is x. Answer A
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