The perimeter of a certain isosceles right triangle is ~$16+16\sqrt{2}$~. What is the length of the hypotenuse of the triangle?


8

16

~$4\sqrt{2}$~

~$8\sqrt{2}$~

~$16\sqrt{2}$~

考题讲解

题目解析:某等腰直角三角形的周长为 ~$16+16\sqrt{2}$~,那么他的斜边是多长?
题目分析:等腰直角三角形两直角边和斜边的比是~$1:1:\sqrt{2}$~(勾股定理),周长为 ~$16+16\sqrt{2}$~,设直角边长为~$a$~,那么~$2a+\sqrt{2}a=16+16\sqrt{2}$~,求解得~$a=8\sqrt{2}$~,那么斜边长为~$\sqrt{2}a=16$~

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Prep2007E1-PS

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