A certain city with apopulation of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?
10,700
10,800
10,900
11,000
11,100
假设最少的一个X,其他10个最大可以多10%,算1.1X,加起来一共11X+X=12X,132000除以12得11000.
将13200分成11份。最小的和最大的相差不能超过any other district。
试着想这么一个情景,10个区将人口少的机会都分给其中一个,10家超过12000,只有1家低于12000(12000=132000/11)
那么,最小人口区(A)应该满足:其他区人数相等,并且是A的1.1倍。
X+10Y=132000
1.1X=Y
X=11000
no district is to have a population that is more than 10 percent greater than the population of any other district.
=====1.1倍是可以的
两两互相不超过0.1,看成等比数列
两俩不相互超10%
好吧,是两两互相不超过0.1,看成等比数列了……………………