In the figure above, points P and Q lie on the circle with center O. What is the value of s ?
~$\frac{1}{2}$~
1
~$\sqrt{2}$~
~$\sqrt{3}$~
~$\frac{\sqrt{2}}{2}$~
如图,我们从点P作一条垂直于横坐标X轴的线段,与X轴相交于M点,由于P点的坐标是~$(-\sqrt{3},1)$~,所以~$PM=1,MO=\sqrt{3}$~,根据勾股定理,OP=2,即圆的半径等于2。又根据三角函数性质得到∠POM=30°(内角为30°,60°,90°的三角形三边比例为~$1:\sqrt{3}:2$~)。
我们再从点Q作一条垂直于横坐标X轴的线段,与X轴相交他于N点,那么ON=s,QN=t。由于∠POQ=90°,所以∠QON=180°-∠POM-∠POQ=60°,所以△OQN同样是一个内角为30°,60°,90°的三角形,所以~$ON:QN:OQ=1:\sqrt{3}:2$~,因为OQ=PQ=2,所以s=ON=1.
这道题目用全等三角形判定定理更为简便,有兴趣的同学可以尝试。
别脑补,别相当然
被图片迷惑+1
切忌所有形式的“想当然、脑补”
没有想到利用边长比与角度比的关系
There are a simple reason and misconception as to why people find this question confusing:
--> the 90 degree angle between P and Q seems like it is cut perfectly right down the centre >> to make two 45 degree angles.
--> that's why your brain instinctively thinks the answer is r = sq(3), since the distance seems the same from the left and to the right of the origin!
However, that's the trick to this question and that's why it is CRUCIAL that you train yourself to be highly critical and wary of accepting the simple answer!
Upon closer inspection of the question:
P(-sq(3),1)
Which means the triangle beneath point P has:
height = 1
base = sq(3)
meaning >> radius = 2 (30-60-90 triangle)
PQ不一定垂直于Y轴,P和Q点不是对称的两个点。
还可以,s^2+t^2=4 ,和8=(根3+s )^2+(t-1)^2,求得 s=1,稍麻烦一点
s是横坐标。sin30°=1/2,
这个题求Q点的横坐标,跟P点横坐标互为相反数呀,答案有误。
我俩犯的错误一样,题目中并没有告诉我们这两个点是跟y轴对称哦,被图迷惑了。。。。
全等三角形
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