If zy < xy < 0, is |x - z| + |x| = |z| ?
(1) z < x
(2) y > 0
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
所以y不可能是负数,要不然z应该大于x
当y>0时,x>z;当y<0时,z>x。
(1) 若z<x,y>0,那么zx都为负,随便套个数就等于这个公式
(2) y>0就可得x>z,且两个都是负数,同上。
条件一:画坐标轴,能得出
条件二:同一
条件一:z < x,
则z < x< 0,|x| = -x, |z| = -z , |x - z|=x-z
|x - z| + |x| =x-z-x=-z=|z|, 故原题可证;
条件二: y > 0
则z < x< 0,论证同条件一。
1结合if,则自然y>0
2结合if,则自然z
好像是这样的........登录 或 注册 后可以参加讨论