Store S sold a total of 90 copies of a certain book during the seven days of last week, and it sold different numbers of copies on any two of the days. If for the seven days Store S sold the greatest number of copies on Saturday and the second greatest number of copies on Friday, did Store S sell more than 11 copies on Friday?
(1) Last week Store S sold 8 copies of the book on Thursday.
(2) Last week Store S sold 38 copies of the book on Saturday.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
仅条件一:上周四卖了8本,还剩下82本,可以是60、12(周五)、4、3、2、1,也可以是67、5(周五)、4、3、2、1,无法确定,排除A、D
仅条件二:上周六卖了38本,还剩下52本,而周五是剩下的6天里卖的最多的一天,假设周五卖的数没有超过11本(以11本计算),剩下的5天最多是10+9+8+7+6=40本,共计51本,无法达到52本的既定数字,故周五的售数量必定超过11本,选择B
来自 http://page.renren.com/601006204/note/913051439
举反例假设F是11
周六卖了38本,剩下52本,如果第二名的星期五卖的少于等于11本,取极限,当星期五卖11本时,剩余41本,只有5天可供分配,这四天最多卖10+9+8+7+6=40
设周i卖出的数量分别为Xi(i=1、2。。。6、7)
X1+X2+X3+X4+X5+X6+X7=90
其中X6最大,X5第二大,每个数都不相等。
所以由条件二X6=38得:
X1+X2+X3+X4+X5+X7=90-38=52
假设X5等于11,那么其他5个数最大只能是10、9、8、7、6
6+7+8+9+10+11=5111