For any triangle T in the xy-coordinate plane, the center of T is defined to be the point whose x-coordinate is the average (arithmetic mean) of the x-coordinates of the vertices of T and whose y-coordinate is the average of the y-coordinates of the vertices of T. If a certain triangle has vertices at the points (0,0) and (6,0) and center at the point (3,2), what are the coordinates of the remaining vertex?
(3,4)
(3,6)
(4,9)
(6,4)
(9,6)
average (arithmetic mean) of the x-coordinates 除以3而不是除以2
我又错了
写出来就不会错了,还送了个等边三角形
任何在xy 坐标平面的三角形T,T的中心的x坐标为三角形三个顶点X坐标值的算术平均值,y坐标为三顶点的Y坐标值的算术平均值。 如果一个三角形的两顶点分别是(6,0), (0,0),中心为(3,2),那么它另外的一个顶点的坐标是多少?
题目全解:(6+0+X)/3=3 则X=3 (0+0+Y)/3=2 则Y=6 所以坐标为(3,6) from 其他网站
设所求的顶点的y坐标为x
(0+0+x)/3=2
求得x=6
没看懂,求讲解