请问一下 C选项that 也是修饰前面的名词呀，临近conversation，而应该修饰 tool才对吧， 跟D选项问题差不对，为什么C是正确的呢？我当时就因为这个把C/D都排除了

本来选对了，仔细一看，又不知道答案了...

不懂

第二个通分到左右两边消不掉的时候就盲选了，感觉第二个不好算
有容易的算法吗，（2）？

1： x^2+y^2-9=0
x^2-y^2=9+y^2
(x+y)(x-y)=(3+y)(3-y)
x=3 有结论。
2： 没有y,无法得出结论

选A

终于做对了..nice

So much as是对的
As when 排除C
平行结构，排除DB

请问D选项为什么最后是is不是are？

这些题目感觉大部分是做过的。

thx

把条件二想成积是30了，啊啊啊啊

我艹......分子分母都要减Y

为什么c选as much as放后面就不能修饰hours

1）通过电脑和打印机的倍数关系确定二者大小关系，电脑C最多是打印机P的3倍，也就是C ≤ 3P
The number of computers can be at most 3 times the number of printers
Let C = the number of computers purchased
Let P = the number of printers purchased
So, we can write: C ≤ 3P
Subtract 3P from both sides of the inequality to get: C - 3P ≤ 0

2）买电脑和打印机一起的钱z最多不超过是$9100
Computers cost $1,500 each, and printers cost $300 each.
So, the total cost of purchasing C computers and P printers = 1500C + 300P

What is the greatest number of computers can the company buy if it has a total of $9,100 to spend on computers and printers?
This tells us that the total cost cannot exceed $9100
So, we can write, 1500C + 300P ≤ 9100

3）联立不等式，求得C的范围
We now have the following system of inequalities:
C - 3P ≤ 0
1500C + 300P ≤ 9100

Take the top inequality and multiply both sides by 100 to get:
100C - 300P ≤ 0
1500C + 300P ≤ 9100

Since the inequality symbols are facing the same direction, we can add the two inequalities to get: 1600C ≤ 9100
Divide both sides of the inequality by 1600 to get: C ≤ 9100/1600
Simplify to get: C ≤ 5.something

C最大是5

T=40/60=2/3
T1=20/50=2/5
T2=2/3-2/5=4/15
S2=20/(4/150)=75

看不懂为啥是转折关系，既然11月份好卖，卖的更好不是更好解释么

and the time required for a stroke is exactly equal to the time interval between strokes
敲钟和间隔时间一样
敲6次+间隔5次 = 11
22/6 = 2
12+11 = 23
23*2 =46

假设总收入是x

【文字解读有问题】for any week is $360 plus 6 percent of the portion of A's total sales above $1,000 for that week.
翻译：360 + 6% of the 总收入x超过1,000的部分

which will be
360+6%(x-1,000) = 8%x
x = 15,000

因为公约数不能大于两数

这题不给条件也推的出？