Each of the five divisions of a certain company sent representatives to a conference. Ift he numbers of representatives sent by four ofthe divisions were 3, 4, 5, and 5, was the range of the numbers of representatives sent by the five divisions greater than 2?
(1)The median of the numbers of representatives sent by the five divisions was greater than the average (arithmetic mean) of these numbers.
(2)The median of the numbers of representatives sent by the five divisions was 4.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
情况1:中间数>平均数 假设第5部门派遣?位员工
假设中间数=5, 5>(17+?)/5 ?<8. 又因为中间数假设为5,所以这种情况5<=?<8, ?可能=5.6.7其中之一
假设中间数=4 4>(17+?)/5 ?<3. 又因为中间数假设为4. 所以这种情况?可能=0,1,2其中之一
问5个部门派遣人数是否范围比2大。当?=0,1,2,6,7时,范围比2大。但有可能?=5,这时中间数不会大于平均数。所以情况1不绝对成立。不充足
情况2:中间数=4. ?可能=0,1,2,3,4其中之一。 当?=0,1,2时,范围比2大。 ?=3,4时,范围为2. 情况2也不绝对。不充足
情况1+2. 就是中间数=4 ,同时 中间数>平均数。 4>(17+?)/5 ?<3. 又因为中间数为4. 所以这种情况?可能=0,1,2其中之一。不管?=0,1,2的哪个数。范围都比2大。所以选C。
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