If 1050 – 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
424
433
440
449
467
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10^x - 74 --> last 2 digits are always 2, 6. 10^2 - 74 = 26 10^3 - 74 = 926 10^4 - 74 = 9926 and so on.... If x > 1, the sum of the digits --> (x-2) * 9 + 2 + 6. hence, (50-2) * 9 + 8 --> 440.
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10^x - 74 --> last 2 digits are always 2, 6.
10^2 - 74 = 26
10^3 - 74 = 926
10^4 - 74 = 9926 and so on....
If x > 1,
the sum of the digits --> (x-2) * 9 + 2 + 6. hence, (50-2) * 9 + 8 --> 440.
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