Last year all refuse collected by Shelbyville city services was incinerated. This incineration generated a large quantity of residual ash. In order to reduce the amount of residual ash Shelbyville generates this year to half of last year's total, the city has revamped its collection program. This year city services will separate for recycling enough refuse to reduce the number of truckloads of refuse to be incinerated to half of last year's number.
Which of the following is required for the revamped collection program to achieve its aim?
This year, no materials that city services could separate for recycling will be incinerated.
Separating recyclable materials from materials to be incinerated will cost Shelbyville less than half what it cost last year to dispose of the residual ash.
Refuse collected by city services will contain a larger proportion of recyclable materials this year than it did last year.
The refuse incinerated this year will generate no more residual ash per truckload incinerated than did the refuse incinerated last year.
The total quantity of refuse collected by Shelbyville city services this year will be no greater than that collected last year.
情景:去年Shelbyville城收集的垃圾都被焚烧掉了。焚烧产生了大量灰烬。为了把灰烬减少到去年的一半,Shelbyville城修改了垃圾收集计划,今年决定回收再利用一些垃圾,以此来使焚烧的垃圾数量减半。
推理:由于本题的问题问的是方案,所以肯定为方案推理。
本题的推理结构为:
目标:使焚烧的垃圾数量减半
方案:Shelbyville城修改了垃圾收集计划,今年决定回收再利用一些垃圾
选题方式:方案推理有三个评估方向,简而言之,即,答案选项一定和方案的内容相关。
选项分析:
A选项:今年,城市可以分类回收的垃圾将不会被焚烧。本选项讨论的是哪种垃圾会(不会)被焚烧,和城市的方案没有关系。
B选项:将可回收的垃圾分类的费用少于去年处理灰烬的费用。本选项讨论的是城市的成本问题,由于推理文段中并没有说政府花不起处理灰烬的费用,所以本选项不能评估方案推理。
C选项:今年所收集的垃圾比去年包括更大比例的可回收垃圾。本选项讨论的是今年回收的垃圾的性质,和方案无关。
D选项:Correct. 今年所焚烧的垃圾,每车垃圾产生的灰烬不比去年多。如果今年回收的垃圾产生的灰烬更多,那么纵然垃圾总量少了一半,灰烬数来时不怎么容易减小,让方案无法达成目标。属于CQ1:方案的可行性问题。
E选项:今年收集的垃圾总量不比去年多。如果今年收集的垃圾比去年多,那么该选项可以在一定程度上削弱方案推理,但是强度不那么强,因为就算是垃圾更多,也可能被分类出来的更多,继而可以减少至去年的一半。
看了半天,我少看了条件 ...
This year city services will separate for recycling enough refuse to reduce the number of truckloads of refuse to be incinerated to half of last year's number
这就话说will..... will是100%的意思 ... 所以E 选项才会被排除 。这句话意思就是无论如何,今年用来燃烧的truckload的数量将会被减到只有去年的一半....垃圾多了,少了,都会被控制到去年一半
所以在这个前提下,才有D的合理性 X(ash总量)= M (truckload数 )* N(单位车产生的ash ) .... 1/2 X = 1/2 M * N
没有这句话,D和E选项就是一样的 ,就成了数学题,必须有个参照数据才能决定哪个效果大
看了一圈下来,我觉得你的解释是最有道理的,关键是在于对这句话的理解。OG对E项的解释感觉不好。
+1
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