If the average (arithmetic mean) of n consecutive odd integers is 10, what is the least of the integers?
(1) The range of the n integers is 14.
(2) The greatest of the n integers is 17.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
题目分析:
(1) 设最小值为k,如果n的范围为14,序列中的所有奇数为k、k+2、k+4、…、k+14共8个数,又因为平均值为10,所以(k+k+2+k+4+…+k+14)/8=10,解得k=3,题目得解。
(2) 序列中的最大值为17,题目要求序列平均值为10,即和为80,因为1~17中所有奇数的和为81,不满足要求,2~17中所有奇数的和为80,满足要求。其余均不满足要求。所以序列最小值为3。题目得解。
因此,本题答案为(D),任何一个条件说明均能解题。
他没说不可以是负数啊??????
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