If x, y, and z are integers and xy + z is an odd integer, is x an even integer?
(1) xy + xz is an even integer.
(2) y + xz is an odd integer.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
求解答
刚刚看了下我是这样理解的,首先做这道题要知道两个数相加A+B,若为偶数,则AB同奇或同偶;若为奇数,则AB一奇一偶。若A*B为偶,则AB中至少有一个偶数。
条件:xy+z为奇
xy+xz为偶
1.假设xy为奇数,则Z为偶数,那么XZ为偶数,那么xy+xz不可能为偶数,不成立
2.假设xy为偶数,则Z为奇数,由第二个条件可知,xz必须为偶数,那么X就必须为偶数
所以选A(题干给的第二个条件推不出来)
楼上正解 同意
一奇+一偶=奇数, 一奇*一偶=偶数 这样理解 列个表快一点,谢谢你
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