The integers m and p are such that 2 < m < p and m is not a factor of p. If r is the remainder when p is divided by m, is r > 1 ?
(1) The greatest common factor of m and p is 2.
(2) The least common multiple of m and p is 30.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
笔记:
题干:2 < m < p, p=km+r, r > 1 ? (m is not a factor of p,就是不能整除的意思)
条件1:最大公约数是2,别管俩人里面还有啥,一个有3,一个没有3,或者一个有5,一个多个7,反正pm都是偶数
p=km+r ,p偶数,km偶数,r也偶数,最小是2(余数肯定大于等于1)满足
看是AD
条件二:最小公倍数 m and p ,30.
30=3*2*5
拆一下,他俩分别是
5, 6
3,10,
2,15
都余数是1
但是还可以拆(最小公倍数,是取俩数都有的质因数最大次幂)
6和15,就余数是3
不满足
还有10和15,余数是5
所以选A
登录 或 注册 后可以参加讨论